Question

A box contain 3 defective mangoes and 21 good mangoes. One mango is drawn from the box at random. Find the probability of getting:- a) defective mango b) good mango.​

Answer 1

Answer:

ans

Step-by-step explanation:

Given : A box contains 3 defective mangoes and 21 good mangoes. one mangoes drawn from the box at random.

To find : The probability of getting

i) a defective mangoes

ii) a good mangoesGiven : A box contains 3 defective mangoes and 21 good mangoes. one mangoes drawn from the box at random.

To find : The probability of getting

i) a defective mangoes

ii) a good mangoes

Solution :

A box contains 3 defective mangoes and 21 good mangoes.

Total number of mangoes = 3+21=24

Solution :

A box contains 3 defective mangoes and 21 good mangoes.

Total number of mangoes = 3+21=24

Answer 2

Answer:

21/24

Step-by-step explanation:

probability of getting good mangoes