Question

A box contain 4 black beads and 3 white beads .Another box contains 5 black beads and 7 white beads .One is taken from each box.
a) what is the probability of both being black
C)what is the probability of getting atleast one black bead​

Answer 1

Answer:

a =17/35

b = 3/7

Step-by-step explanation:

solution----->

Given:-

box A = 8 black beads and 12 white beads

Box B = 9black and 6 white beads

as per condition

S = {B,B,B,B,B,B,B,W,W,W,W,W,W,W,W,W,W,W,W

B,B,B,B,B,B,B,B,B,W,W,W,W,W,W}

n (s)= 35

now as per first condition

A = {B,B,B,B,B,B,B,B,B,B,B,B,B,B,B,B,B}

n (A)= 17

acording to 2nd condition

B ={B,B,B,B,B,B,B,B,W,W,W,W,W,W}

n (B)= 15