Question

A box contain 4 blue balls and 5 green balls Four ball drawn randomly without replacement what is the probability of that two blue ball and two green balls

Answer 1

Answer:

probability=4/9= 3/2

Answer 2

The probability of that two blue balls and two green balls is $\frac{5}{27}$

Step-by-step explanation:

A box contain 4 blue balls and 5 green balls. Four balls are drawn randomly without replacement.

First two blue balls are drawn then two green balls.

Probability =  

$\frac{4}{9}\times \frac{3}{8}\times \frac{5}{7} \times \frac{4}{6}\\= \frac{5}{27}$

Hence, the probability of that two blue balls and two green balls is $\frac{5}{27}$