a box contain 4 oranges ,6 apples & 5 mangoes . one fruit is drawn at random from the box . what is the probability that the fruit drawn is (a)an orange ? (b) not a mango ?
Answers
orange drawn at random 4/15
b) not a mango= 15-10= 5
5/15= 1/3
Answer:
A box holding 4 lemons, 6 apples, and 5 mangoes is presented in this challenge. We are instructed to calculate the likelihood of drawing a particular variety of fruit from the package.
Step-by-step explanation:
This query consists of two parts:
a) How likely is it that I will select an orange from the box?
b) What is the likelihood that the package won't contain a mango?
Let's take a closer look at each of these components.
a) Odds of getting an orange out of the box:
The package contains a total of 4 + 6 + 5 = 15 vegetables. There are four lemons among them. As a result, the likelihood of pulling an orange from the box is determined by:
Number of oranges / Total quantity of foods = 4 / 15 = 0.2667; probability of getting an orange (rounded to four decimal places)
As a result, there is a 26.67% chance of pulling an orange from the package, or about 0.2667.
b) Chances of not taking a mango out of the box:
The package contains a total of 4 + 6 + 5 = 15 vegetables. There are five bananas among them. As a result, the likelihood of pulling a mango from the package is determined by:
Probability of picking mangoes = number of mangoes / total number of fruits
= 5/15
= 0.3333 (rounded to four decimal places)
To find the probability of picking a mango, we can subtract the probability of picking a mango from 1. This is because the probability of drawing a mango or not drawing a mango is always 1. So we have:
probability of not picking a mango = 1 - probability of picking a mango
= 1 - 0.3333
= 0.6667 (rounded to four decimal places)
So the probability of not taking a mango out of the box is about 0.6667 or 66.67%.
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