Question

a Box contain 50 bulbs if 10 were broken what fraction of the bulbs were broken and what fraction of the bulbs were unbroken ?write an equilavent fraction using the denominator of 100 for each answer

Answer 1

Answer:

80will be the required numerator

hope it helps u and pls mark as brainliest

Answer 2

Given:-

➜ Total bulbs = 50

➜ Broken bulbs = 10

➜ Unbrroken bulbs = 50-10 = 40

$\bf\large\underline\blue{Solution :-}$

➜ Fraction for broken bulbs = 10/50 = 1/5

➜ Faction for unbroken bulbs = 40/50= 4/5

May it will help you !