Question

A box contains 10 balls
3 Red and Dotted,1 Red and stripped 2 Grey and doted
4 Grey and stripped. what is the probability that a ball selected at random is
1) dotted and grey 2) stripped and red 3) grey and stripped 4) red and dotted​

Answer 1

Answer:

1-1/5

2-1/10

3-2/5

4-3/10

Answer 2

$\huge \mathfrak \fcolorbox{red}{red}{ \fcolorbox{yellow}{yellow}{ \fcolorbox{green}{green}{ \fcolorbox{blue}{blue}{ \fcolorbox{indig}{indigo}{ \fcolorbox{violet}{violet}{ \fcolorbox{white}{white}{ \blue{ answer} }}}}}}}$

1\5

1\10

2\5

3\10

Step-by-step explanation:

SOLUTION

total number of balls=3+1+2+4=10

• number of dotted and grey ball=2
• number of stripped and red ball=1
• number of grey and stripped ball= 4
• number of red and dotted ball =3

• part one

2\10

=1\5

• part two

1\10

• part three

4\10

=2\5

• part four

3\10

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