Question

a box contains 10 red marbles 20 blue marbles and 30 green marbles. 5 marbles are drawn from the box. what is the probability that 1 all will be blue 2 atleast one will be green

Answer 1

Given that red marbles in the box = 10.

Given that blue marbles in the box = 20.

Given that green marbles in the box = 30.

Total number of marbles in the box = 10 + 20 + 30

                                                            = 60.

Let S be the event that 5 marbles are drawn from the box.

n(S) = 60c5.


(1) All will be blue.

Let A be the event that all will be blue.

n(A) = 20c5/60c5

        = (20!/5!(20-5)!)/(60!/5!(60-5)!)
 
        = 15504/5161512


(2) At least one will be green:

Let B be the event that at least one will be green.

n(B) = 1 - P(no marbles are green)

        = 1 - 30C5/60C5.

        = 1 - 142506/5161512

        = 5019006/5161512.


Hope this helps!

Answer 2

Answer:

Step-by-step explanation:

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