A box contains 10 screws, 3 of which are defective. Two screws are drawn at random with replacement. The probability that none of the two screws is defective will be
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The probability of the 2 screws is = 2/3
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I hope it is helps you .
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Answer:
49/100
Step-by-step explanation: for one draw,
P(defective) = 3/10
P(not defective) =7/10
Since we are selecting with replacement,
P(not defective) = (7/10) * (7/10) = 49/100
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