A box contains 11 balls, numbered 1, 2, 3, …, 11. if 6 balls are drawn simultaneously at random, what is the probability that the sum of the numbers on the balls drawn is odd?
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total balls=11
outcomes are 1+2+3+4+5+6=21
1+2+4+5+6+7=25
1+2+3+5+6+8=25 ..........
out of all outcomes you will get 9 outcomes
so the probability will be 9/11
outcomes are 1+2+3+4+5+6=21
1+2+4+5+6+7=25
1+2+3+5+6+8=25 ..........
out of all outcomes you will get 9 outcomes
so the probability will be 9/11
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