A bus starts running with some initial speed and its speed increases every hour by 9 km/hr. if it takes 11 hours to cover a distance of 572 km, then what was the initial speed (in km/hr) of the bus? solution
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a = 9km/h^2
t = 11h
S = 572km
S = ut + 0.5at^2
572 = 11u + 0.5*9*11^2
572 = 11u + 544.5
11u = 572 - 544.5
u = (572 - 544.5) / 11
u = 2.5 km/h
Initial speed is u = 2.5 km/h
t = 11h
S = 572km
S = ut + 0.5at^2
572 = 11u + 0.5*9*11^2
572 = 11u + 544.5
11u = 572 - 544.5
u = (572 - 544.5) / 11
u = 2.5 km/h
Initial speed is u = 2.5 km/h
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