Question

A box contains 17 cards 1, 2, 3, …., 17 and are mixed thoroughly. A card is drawn at random from the box. Find that the number on the card is: (a) even (b) odd (c) prime. ​

Answer 1

Given A box contains 17 cards numbered 1 to 17 So, total number of outcomes = 17

(a) Odd numbers (1, 3, 5, 7, 9, 11, 13, 15, 17) = 9. Therefore, Probability = $\frac{9}{17}$

(b) Even numbers (2, 4, 6, 8, 10, 12, 14, 16) = 8. Therefore, Probability = $\frac{8}{17}$

(c) Prime numbers (2, 3, 5, 7, 11, 13, 17) = 7. Probability = $\frac{7}{17}$

Answer 2

Answer:

A box contains 17 cards from 1 to 17

::Sample space ( S ) = { 1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17 }. n(S) = 17

(a). Let 'A' be the event in which card is even =

A = { 2,4,6,8,10,12,14,16 }. n(A) = 8

(b). Let 'B' be the event i n which card is odd=

B = {1,3,5,7,9,11,13,15,17 }. n(B) = 9

(c). Let 'C' be the event in which card is prime =

C = {2,3,5,7,11,13,17 }. n(C) = 7

A....8

B....9

C....7