A box contains 2 blue caps 4 red caps 5 green caps and 1 yellow cap.if 4 caps are picked at random then what is the probability that nkne is green?
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You have total # caps = 12, non-red = 8 caps and 4 red caps.
By the complement rule: P(at least one red cap picked) = 1 - P(no red caps picked)
P(no red caps picked) =(82)(122)=(82)(122)
P(at least one red cap picked) = 1−(82)(122)1−(82)(122)
So the probability that at least one red cap is picked when 2 caps are picked at random is 19331933 or 0.57576.
By the complement rule: P(at least one red cap picked) = 1 - P(no red caps picked)
P(no red caps picked) =(82)(122)=(82)(122)
P(at least one red cap picked) = 1−(82)(122)1−(82)(122)
So the probability that at least one red cap is picked when 2 caps are picked at random is 19331933 or 0.57576.
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