Question

a box contains 28 bulbs of which 7 bulbs are defective, a bulb is drawn randomly from box. find the probability of picking a non defective bulb.​

Answer 1

Answer:

3/4=0.75

Step-by-step explanation:

total no. of bulbs=28

total no.of defective bulbs=7

total no. of non defective bulb =28-7=21

then the probability would be =21/28=3/4

hope this answer helps you :)