A box contains 36 tickets numbered 1 to 36, 1 ticket drawn at random. Find the probability that the number on the ticket is either divisible by 3 or is a perfect square .
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PROBABILITY
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NUMBER OF TICKETS = 36
NUMBER DIVISIBLE BY 3 =
3,6,9,12,15,18,21,24,27,30,33,36
PERFECT SQUARE = 1,4,9,16,25,36
COMMON NUMBER = 9,36
FAVOURABLE OUTCOMES = 16
TOTAL OUTCOMES = 36
PROBABILITY = 16 /36
ANSWER IS = 4/9
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NUMBER OF TICKETS = 36
NUMBER DIVISIBLE BY 3 =
3,6,9,12,15,18,21,24,27,30,33,36
PERFECT SQUARE = 1,4,9,16,25,36
COMMON NUMBER = 9,36
FAVOURABLE OUTCOMES = 16
TOTAL OUTCOMES = 36
PROBABILITY = 16 /36
ANSWER IS = 4/9
PLEASE FOLLOW VIRATANMOL
MARK ME BRAINLIEST
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