Question

A box contains 36 tickets numbered from 1 to 36. One ticket is drawn at random. Find the probability that the number
on the ticket is either divisible by 3 or a perfect square​

Answer 1

Answer:

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Answer 2

Step-by-step explanation:

Total number of possible outcomes=36

P(E)=Number of outcomes favourable to E/Total number of possible outcomes

Numbers divisible by 3 or a perfect square between 1 and 36 are-

1,3,4,6,9,12,15,16,18,21,24,25,27,30,33 and 36

i.e.,16 outcomes.

P(Numbers divisible by 3 or a perfect square between 1 and 36)=16/36

                                                                                                           =4/9

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