Question

A box contains 4 tickets which are given numbers as 1,2,3,4 and
another box contains 6 tickets which are given numbers 2,4,6,7,8,
9. A box is selected at random and a ticket is taken from it at random.
Find the probability that the number on the ticket is :
(1) 2 or 4 (ii) 3 (iii) 1 or 9
[Guj. Umi.]​

Answer 1

$|\Omega|=4\cdot 6=24$

1.

$|A|=2+2=4\\\\P(A)=\dfrac{4}{24}=\dfrac{1}{6}$

2.

$|A|=1\\\\P(A)=\dfrac{1}{24}$

3.

$|A|=2\\\\P(A)=\dfrac{2}{24}=\dfrac{1}{12}$