Question

A box contains 5 green, 7 yellow, and 10 orange ping-pong balls. On how many ways can 5 balls be selected if two must be green?

Answer 1

There would be 6800 possible ways.

Step-by-step explanation:

Given,

Green balls = 5,

Yellow balls = 7,

Orange ping-pong balls = 10,

Thus, the number of ways of selecting any 5 balls in which two are green,

$=^5C_2\times ^{17}C_3$

$=\frac{5!}{2!3!}\times \frac{17!}{3!14!}$

$=10\times 680$

$=6800$

#Learn more :

A bag contains 5 red balls and 7 green balls and 8 yellow balls a ball is selected at random from the bag find the probability of getting a yellow ball and non yellow ball

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