A box contains 5 red, 4 white and 3 green balls. In how many ways can 3 balls be drawn from the box, without replacement, so that at least 2 of them are green?
Answers
Answer:
The Answer is 23 / 110
Step-by-step explanation:
Given,
A box contains 5 red, 4 white and 3 green balls
Total number of balls = 5 + 4 + 3
Three balls randomly can be picked in ¹²C₃ ways, that is,
220 ways
According to question,
Atleast 2 of the balls should be green :
CASE 1 :
2 Green balls, 1 Other ball
Number of ways 2 Green balls can be drawn out of total 3 green balls is :
³C₂ ways = 3 ways
1 other balls from the other left balls = ⁹C ₁ = 9 ways
So,
2 Green balls and 1 other ball, Number of ways = 3 * 9 = 45 ways
Case 2 :
All the 3 balls are Green
Number of ways = ³C₃ = 1 way
So, three balls drawn in (45 + 1) = 46 ways will have at least two green balls among the drawn ones
So, the probability of getting at least three Green balls among the three drawn =
( 46 / 220 ) = ( 23 / 110 )
Hence,
The Answer is 23 / 110
Answer:
Step-by-step explanation:
A box contain 3 red, 4 white and 5 green balls. Three balls are drawn at random and replace one after the other. What is the probability that the first is green, the second is white and the third is green ( green, white, green)