A box contains 5 red marbels, 8 white marbles and 4 green marbles, One marble is taken out of the box at ramdom. What is the probability that the marble taken out will be
(i)red?
(ii)white?
(iii)not green?
Answers
SOLUTION :
GIVEN : Number of red marbles = 5
Number of white marbles = 8
Number of green marbles = 4
Total number of marbles in a bag = 5 + 8+4 = 17
Total number of outcomes = 17
(i) Let E1 = Event of selecting that a marble drawn is red
Number of red marbles = 5
Number of outcome favourable to E1 =5
Probability (E1) = Number of favourable outcomes / Total number of outcomes
P(E1) = 5/17
Hence, the required probability of getting a red marble , P(E1) = 5/17.
(ii) Let E2 = Event of selecting that a marble drawn is white
Number of white marbles = 8
Number of outcome favourable to E2 = 8
Probability (E2) = Number of favourable outcomes / Total number of outcomes
P(E2) = 8/17
Hence, the required probability of getting marble drawn is white, P(E2) = 8/17.
(ii) Let E3 = Event of selecting that a marble drawn is not green
Number of not green marbles = (5+8)= 13
Number of outcome favourable to E3 = 13
Probability (E3) = Number of favourable outcomes / Total number of outcomes
P(E3) = 13/17
Hence, the required probability of getting marble drawn is not green , P(E3) = 13/17.
HOPE THIS ANSWER WILL HELP YOU….
Red marbles=5
So its probability=5/17
White marbles=8
So its probability=8/17
Marbles which are not green in colour=13
So its probability=13/17