Question

A train starts from station and move with an constant acceleration for 2 minutes if its cover a distance of 400 m in this period find the acceleration

Answer 1

using second equation of uniformly accelerated motion.

time taken = 2×60 = 120 seconds.
$s = ut + \frac{1}{2} a {t}^{2} \\ 400 = 0 + \frac{1}{2} \times a \times {120}^{2} \\ 400 = \frac{a}{2} \times 14400 \\ 800 = 14400 \times a \\ a = \frac{800}{14400} \\ a = \frac{1}{18} m {s}^{ - 2}$

★PLZ MARK IT AS BRAINIEST ANSWER★
AND DROP A ♥