Question

A box contains 5 red marbles, 6 white marbles and 4 green marbles. If a marble is drawi
random from the box, then answer the questions from 1 to 6.
what is the probability that the marble will be any one colour (a)1/ 6
(b) 1/2
(c) 1
(d) 0​

Answer 1

Step-by-step explanation:

P(getting a red marble) = $\frac{5}{15} \\ = \frac{1}{3}$

P(getting a white marble) = $\frac{6}{15} \\ = \frac{2}{5}$

P(getting a green marble) = $\frac{4}{15}$

P(getting a red or white or green marble) = $\frac{1}{3} + \frac{2}{5} + \frac{4}{15} = 1$

HENCE, the probability of getting any one colour is 1.

Answer 2

$\huge{ \underline{ \bold{ᴀɴsᴡᴇʀ....{ \heartsuit}}}}$

P(getting a red marble) = $$\begin{lgathered}\frac{5}{15} \\ = \frac{1}{3}\end{lgathered}$$

P(getting a white marble) = $$\begin{lgathered}\frac{6}{15} \\ = \frac{2}{5}\end{lgathered}$$

P(getting a green marble) = $$\frac{4}{15}$$

P(getting a red or white or green marble) = $$\frac{1}{3} + \frac{2}{5} + \frac{4}{15} = 1$$

HENCE, the probability of getting any one colour is 1.