Question

a box contains 6 red balls, 5 blue balls, and 10 green balls. In how many ways can you choose 3 blue balls or 3 green balls?

Answer 1

Answer: =120

Step-by-step explanation:

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Answer 2

Correct - Question

a box contains 6 red balls, 5 blue balls, and 10 green balls. In how many ways can you choose 3 blue balls and 3 green balls?

Answer:

The number of ways  3 blue balls and  3 green balls can be choosen is  1200.

Step-by-step explanation:

Given:

6 red balls, 5 blue balls, and 10 green balls are contained in the box.

To Find:

The number of ways  3 blue balls and 3 green balls can be choosen.

Solution:

As given- 6 red balls, 5 blue balls, and 10 green balls are contained in the box.

The number of way to choose 3 blue balls out of 5 blue ball $=5C_{3}$

$=\frac{!5}{!(5-3)\ !3}$

$=\frac{!5}{!2\ !3} =10$

The number of way to choose  3 green  balls from 10 green balls  $=10C_{3}$  

$=\frac{!10}{!(10-3)\ !3}$

$=\frac{!10}{!7 \ !3} =120$

The number of ways  3 blue balls and  3 green balls can be choosen $=5C_{3} \times 10C_{3}$

$= 10\times120 =1200$

Thus, the number of ways  3 blue balls and 3 green balls can be choosen is 1200.