Question

a box contains 6 red balls and 2 black balls two are drawn random from it without replacement if x denotes no.of balls drawn then E(x) us equal to

Answer 1

TOTAL BALLS = 6 RED + 2 BLACK = 8 BALLS
TOTAL WAYS TO DRAWN TWO BALL WITHOUT REPLACEMENT IS 8C2 = 8!/6!×2! = 28

SO E(X) = 28

Answer 2

Answer:

The required value of E(X) when x = 2 is 28

Step-by-step explanation:

Number of red balls in the box = 6

Number of black balls in the box = 2

Total number of balls in the box = 6 + 2 = 8

Let x denotes the number of balls to be drawn from the box

We need to draw two balls from the box ⇒ x = 2

So, E(X) when x = 2 and without replacement is given by :

$E(X = 2) =\:\:_{2}^{8}\textrm{C}\:\:= 28$

Thus, The required value of E(X) when x = 2 is 28