Question

* A Box Contains 6 white and 4 green balls. If two
balls are drawn at random find the probability
that they are either white or green balls.​

Answer 1

 ANSWER

Let S be the sample space

Then n(S) = no of ways of drawing 2 balls out of (6+4) =10C2 10 =10*92*1 =45

Let E = event of getting both balls of same color

Then, n(E) = no of ways (2 balls out of six) or (2 balls out of 4)

               =6C2+4C2 = 6*52*1+4*32*1= 15+6 = 21

Therefore, P(E) = n(E)/n(S) = 21/45 = 7/15