Question

a box contains 6 white wall and 3 black balls and another box contains 4 white balls 5 black balls what is the probability that a ball selected from one of the box at random is white ball. ​

Answer 1

Answer:

i hope this will help u. here u need to take total no of white balls upontotal no of balls in both boxes

Answer 2

Given: A box contains 6 white balls and 3 black balls and another box contains 4 white balls and 5 black balls.

To find: The probability that a ball selected from one of the box at random is white ball.

Solution:

Probability of an event is the chances its occurrence. It is calculated by dividing the total number of favourable outcomes by the total number of possible outcomes.

First, the probability of selecting one of the boxes is calculated. The number of possible outcomes is 2 and the number of favourable outcomes is 1 because only one box is selected out of the two. Hence, the probability will be 1/2.

The probability of selecting a white ball from the first box would be 6/9 because there are 6 white balls and a total of 9 balls. Similarly, the probability of selecting a white ball from the second box is 4/9 because there are 4 white balls and a total of 9 balls.

Now, the probability that a ball selected from one of the boxes at random is a white ball is calculated as follows.

$(\frac{1}{2} *\frac{6}{9}) + ( \frac{1}{2} * \frac{4}{9} )$

We use a plus sign because the ball is chosen either from the first box or from the second box.

$\frac{3}{9} + \frac{2}{9} = \frac{5}{9}$

Therefore, the probability that a ball selected from one of the box at random is white ball is 5/9.