Question

A box contains 7 red, 6 white and 4 blue balls. How many selection of
three balls can be made so that all three are red balls?
​

Answer 1

Answer:

35 ways

Step-by-step explanation:

7 Red

6 white

4 blue

Given all the balls are red

Number of balls selected =3

Total number of ways of selection

⁷C₃

$→\frac{7!}{4!×3!}$

$→\frac{7×6×3}{6}$

$→\frac{210}{6}$

$→35$

There are 35 ways