Question

a box contains 75 tickets numbered 1 to 75 a ticket is drawn at random from the box what is the probability that
(a)number on ticket is divisible by 6
(b) number on ticket is a perfect square
(c)number on ticket is a prime (d)number on ticket is divisible by 3 and 5​

Answer 1

Answer:

total tickets =75

1. number dividable by 6 =12

p(e)=12/75 =4/25

2. perfect square=8

p(e)=8/75

3. prime numbers=21

p(e)=21/75=7/25

Answer 2

I) 4/25

II) 8/75

III) 7/25

IV) 7/15

There are 75 tickets numbered between 1 to 75.

Total numbers between 1 to 75 that are divisible by 6 = 12

Probability of getting a number divisible by 6 = 12/75 = 4/25

Total numbers between 1 to 75 that are a perfect square = 8

Probability of getting a perfect square number = 8/75

Total prime numbers between 1 to 75 = 21

Probability of getting a prime number = 21/75 = 7/25

Total numbers between 1 to 75 that are divisible by 3 or 5 = 35

Probability of getting a number divisible by 3 or 5 = 35/75 = 7/15