Question

A box contains 80 dics which are numbered from 1 to 80. if one dics is drawn at random from the box, find the probability that it bears a perfect square number??

Answer 1

Hello dear ,
Here is your answer ,

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Total number of outcomes = 80.

Let E1 be the event of getting a perfect square number.

Out of these numbers, perfect square numbers are 1, 4, 9, 16, 25, 36, 49 and 64.

Thus, number of favourable outcomes = 8.

∴ P(getting a perfect square number) = P(E1) 

$\frac{number \: of \: favourable \: outcomes}{number \: of \: all \: possible \: outcomes}$
$= \frac{8}{80} = \frac{1}{10}$
Thus, the probability that the disc bears a perfect square number is 110.

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