Question

a box contains 90 discs numbered from 1 to 90. if one disc is drawn out at random from the box,what is the probability that it bears a prime number less than 23.

Answer 1

I/10 is answer 1,2,3,5,7,11,13,17,19,23 all r 1prime no less than 23

Answer 2

Answer:

The probability is $\frac{4}{45}$.

Step-by-step explanation:

Given : A box contains 90 discs numbered from 1 to 90. if one disc is drawn out at random from the box.

To find : What is the probability that it bears a prime number less than 23?

Solution :

$\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}$

Favorable outcomes (a prime number less than 23) are 2,3,5,7,11,13,17,and 19

Number of favorable outcomes = 8

Total number of outcomes = 90

$\text{Probability}=\frac{8}{90}$

$\text{Probability}=\frac{4}{45}$

Therefore, The probability is $\frac{4}{45}$.