a box contains a certain number of balls. some of these balls are marked A,some are marked B and the remaining are marked C. When a ball is drawn at random from the box p (A)=1/3 and p (B)=1/4.if there are 40 balls in the box which are marked C,find the number of balls in the box
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1-1/3+1/4=12-4-3/12=5/12 . Total no of balls=12/5×40=96balls
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The total number of balls is 96.
Let the total number of balls be X.
Probability of getting A ball is X/3
Probability of getting B ball is X/4
Total probability = 1
Probability of getting a C ball would be 1-X/3 - X/4 = 5X/12
The total number of C balls is 40
Equating both,
40 = 5X/12
X = 96
hence, total balls is 96
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