a box contains card number 11 to 123. A card is drawn at random from the box. Find the probability that the number on the drawn card is a square number and a multiple of 7
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2
1/ total no. of cards
siddhartharao77:
Not a square of 7
yeah?
U have to write all the multiples of 7 between 11 to 123
No it is asked that it is also a square no. and a multiple of seven too.
there are 2 conditions in this questions.(1) card drawn should be a square number. (2) card number should be a mulltiple of 7.
I think that it is only one condition.
No vibhu..There are 2 conditions
there is and statement not or.
Well than siddharth thanks a lot.
Okkk
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Given that total number of cards n(S) = 113.
(1) Let A be the favorable outcomes of getting a square number.
Square numbers from 11 to 123 = 16,25,36,49,64,81,100,121.
n(A) = 8.
Therefore the required probability P(A) = n(A)/n(s)
= 8/113.
(2) Let B be the favorable outcomes of getting a number multiple of 7.
Multiple of 7 between 11 to 123 = 14,21,28,35,42,49,56,63,70,77,84,91,98,105,112,119.
n(B) = 16.
The required probability P(B) = n(B)/n(S)
= 16/113.
Hope this helps!
(1) Let A be the favorable outcomes of getting a square number.
Square numbers from 11 to 123 = 16,25,36,49,64,81,100,121.
n(A) = 8.
Therefore the required probability P(A) = n(A)/n(s)
= 8/113.
(2) Let B be the favorable outcomes of getting a number multiple of 7.
Multiple of 7 between 11 to 123 = 14,21,28,35,42,49,56,63,70,77,84,91,98,105,112,119.
n(B) = 16.
The required probability P(B) = n(B)/n(S)
= 16/113.
Hope this helps!
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