A box contains cards bearing numbers 6 to70. If one card is drawn at random then find the probability that it bears (a) a one digit number (b) a number divisible by 5
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a)P(that it bears a one digit number)= 4/64
=2/32
=1/16
b)p(a number divisible by 5)=12/64
=6/32
=3/16
=2/32
=1/16
b)p(a number divisible by 5)=12/64
=6/32
=3/16
the991:
excuse me but the 2nd one is wrong , please recheck
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here is your solution , sorry for the bad writing
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