a box contains cards numbered 3,5,7,9...,35,37. A card is drawn at random from the box. Find the probability that the numbe on the drawn card is a prime number
Answers
Answered by
173
Hi ,
We know that ,
_______________________________
The probability event E
P( E ) = Number of outcomes favourable to E / Number of all
possible outcomes of the experiment
___________________________________
According to the problem given ,
Number of all possible outcomes =
Number of cards the box contains = 18 -------( 1 )
( 3,5,7,9,11,13,15,17,19,21,23,25,,27,29,31,33,35,37 )
Number of outcomes favourable = 11 ----- ( 2 )
( since prime number cards in the box are
3 , 5 ,7, 11 , 13 ,17 , 19 ,23 , 29 , 31 , 37 )
P( E ) = ( 1 ) / ( 2 )
= 11 / 18
= 0.61111..
= 0.61 ( approx )
I hope this helps you.
***
We know that ,
_______________________________
The probability event E
P( E ) = Number of outcomes favourable to E / Number of all
possible outcomes of the experiment
___________________________________
According to the problem given ,
Number of all possible outcomes =
Number of cards the box contains = 18 -------( 1 )
( 3,5,7,9,11,13,15,17,19,21,23,25,,27,29,31,33,35,37 )
Number of outcomes favourable = 11 ----- ( 2 )
( since prime number cards in the box are
3 , 5 ,7, 11 , 13 ,17 , 19 ,23 , 29 , 31 , 37 )
P( E ) = ( 1 ) / ( 2 )
= 11 / 18
= 0.61111..
= 0.61 ( approx )
I hope this helps you.
***
Answered by
33
Number of favourable outcomes=18
P(of getting a prime number)=11/18=0.66approx
Similar questions