Question

a box contains orange,. mango,and lemon flavoued candies. a candy is drawn randomly. if p (not orange)=11/15 and p(mango)=1/3 then what is the p(lemon)​

Answer 1

Given,

P(Mango) = 1/3

P(Not orange) = 11/15

Now,

P(Orange) = 1 - P(Not orange)

P (Orange) = 1 - 11/15

=( 15 - 11) /15

P (Orange) = 4/15

Now,

P(Orange) + P(Mango) + P(Lemon) = 1

$\frac{4}{15} + \frac{1}{3} + p(lemon) = 1 \\ \\ \frac{4 + 5}{15} + p(lemon) = 1 \\ \\ \frac{9}{15} + p(lemon) = 1 \\ \\ \frac{3}{5 } + p(lemon) = 1 \\ \\ p(lemon) = 1 - \frac{3}{5} \\ \\ p(lemon) = \frac{5 - 3}{5} \\ \\ p(lemon) = \frac{2}{5}$

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