Question

A box of 12 dozen pens contain a dozen defective . one pen is taken out at random what is the probability that the pen taken out is first defective second non defective what

Answer 1

Answer:

1/13

Step-by-step explanation:

A box of 12 dozen pens contain a dozen defective

=> 12 * 12 = 144 Pens

Defective =  12 Pens

Non - Defective = 144 - 12 = 132 pens

probability that the pen taken out is first defective second non defective what

First Defective Probability =  12/144 = 1/12

Second non defective = 132/143

Probability =  (1/12) (132/143)

=   11/143

= 1/13

Answer 2

i ) defective probability = 121/144

= 1/12

ii ) Non defective probability = 132/144

= 11/12