Question

A box of 600 bulbs contain 12 defective bulbs one bulb is taken out of random from box then the probity that is non defective bulb

Answer 1

Step-by-step explanation:

total number of bulbs =600

No. of non defective bulb = 600-12=588

P= Favorable outcome/ Total outcome

P= 588/600

Or

P= 49/50

Probability of non defective bulb

I hope it helps

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