Question

a box of 600 electric bulbs contains 12 defective bulbs one bulb is taken out at random from this box what is the probability that it is a non defective bulb

Answer 1

Answer:

The probability that one bulb taken out random is non-defective is $\dfrac{49}{50}$ .

Step-by-step explanation:

Given as :

The number of bulb in the box = 600

The number of defective bulb in box = 12

Let The probability that one bulb taken out random is non-defective = p(E)

According to question

As out of 600 bulbs, 12 bulbs are defective

So, The number of non-defective bulb = 600 - 12 = 588

Now, out of 600 bulbs, 1 bulb is chosen in ${C_{1}}^{600}$

And favourable case of chosen non-defective = ${C_{1}}^{588}$

So, probability = $\frac{{C_{1}}^{588}}{{C_{1}}^{600}}$

Or, p(E) = $\dfrac{588}{600}$

Or, p(E) = $\dfrac{49}{50}$

Hence, The probability that one bulb taken out random is non-defective is $\dfrac{49}{50}$ . Answer

Answer 2

Answer:

THE ANSWER TO THIS QUESTION IS 49/50