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In triangle abc ab=bc
so angle cab = angle acb = 40 °
angle dca = 40° (corresponding to angle acb)
angle adc = 180 - 80 ° = 100 ° (angle sum property of a triangle )
so angle cab = angle acb = 40 °
angle dca = 40° (corresponding to angle acb)
angle adc = 180 - 80 ° = 100 ° (angle sum property of a triangle )
Answered by
1
40 is the corresponding angle in angle dac
40+40=180
=>80=180
=>180-100
=>80
hope it helps
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