Question

a box of 600 electric bulbs contains 12 defective bulbs one bulb is taken out at random from this box what is the probability that it is not defective​

Answer 1

Answer:

Out of 600 electric bulbs one bulb can be chosen in 600 ways

⇒Total number of outcomes = 600

Number of non-defective bulbs = 600 -12

= 588

⇒ Number of favourable outcomes = 588

P(Getting a non-defective bulb) = No. of favourable outcomes÷Total no. of outcomes

⇒ Probability = 588/600

=> 49/50

Hence, the probability of getting a non-defective bulb = 0.98

Answer 2

total bulbs=600

defective bulbs=12

non-defective bulbs=600-12

=588

prob.(not defective)=588/600

=294/300

=147/150

=49/50

prob.=49/50

or

0.98..

hope this helps✌✌