"A box of mass 150g threw with a speed of 45m/s and it stop after 0.15second. find the distance, force and acceleration."
Answers
Answered by
0
Answer:
Distance = speed * time
= 45 * 0.15 = 6.75 m
Acceleration = (v-u) /t
= (0 - 45)/0.15
= - 300 m/s^2
Force = mass * acceleration
= (150/1000) * - 300 = - 45 N
Hope this helps you..
Similar questions
Math,
4 months ago
Hindi,
4 months ago
English,
4 months ago
Computer Science,
9 months ago
Hindi,
9 months ago