A box of Q pounds is given to Sanjay, Raj and David. They divided it equally amongst themselves. Then Sanjay gives Raj M pounds. Raj gives David 2M pounds and David gives Sanjay 3M pounds. Afterwards, Sanjay has exactly half of all the pounds initially given to the three people. In terms of M, how much money was originally given to Sanjay, Raj and David
Answers
Initially 12M money was given to Sanjay, Raj and David
Step-by-step explanation:
Initially, pounds with each of person, Sanjay, Raj and David = Q/3
Sanjay gives Raj 2M pounds
∴ Pounds with Sanjay = Q/3-M
Pounds with Raj = Q/3+M
Raj gives David 2M pounds
∴ Pounds with Raj = Q/3+M-2M = Q/3-M
Pounds with David = Q/3+2M
David gives Sanjay 3M pounds
∴ Pounds with David = Q/3+2M-3M = Q/3-M
Pounds with Sanjay = Q/3-M+3M = Q/3+2M
Now Sanjay has exactly half of all the pounds initially given
Therefore,
Q/3+2M = Q/2
or, Q/2-Q/3 = 2M
or, Q/6 = 2M
or, Q=12M
Therefore, initially 12M money was given to Sanjay, Raj and David.
Hope this answer is helpful.
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Q = 12M
Step-by-step explanation:
A box of Q pounds Divided equally between 3
=> Sanjay got = Q/3
Sanjay give Raj M
=> Sanjay has = Q/3 - M
David gives Sanjay 3M
=> Sanjay has = Q/3 - M + 3M = Q/3 + 2M
Q/3 + 2M = Q/2
=> 2Q + 12M = 3Q
=> Q = 12M
12M money was given to Sanjay, Raj and David.
and Each got 4M initially
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