Question

A box of weight 100 N is lifted to a height of 10 m above ground. How much potential energy will be stored in the box?
9800 J
1000 J
2000 J
none of the above​

Answer 1

$\large{\underline{\underline{\sf{ \maltese \: {Given:-}}}}}$

• Weight = 100 N
• Height = 10 m

$\large{\underline{\underline{\sf{ \maltese \: {To \: find:-}}}}}$

Potential energy = ?

$\large{\underline{\underline{\sf{ \maltese \: {Solution:-}}}}}$

➊ We know that:–

$\qquad \bull \bf \: {Weight = Mass \times Acceleration }∙$

$\begin{gathered}\qquad \quad {:} \longrightarrow\sf \: {100 = mass \times 10 } \\\end{gathered}$

$\begin{gathered}\qquad \quad {:} \longrightarrow\sf \: { \dfrac{100}{10} = mass } \\\end{gathered}$

$\begin{gathered}\qquad \quad {:} \longrightarrow\sf \: { mass = \cancel\dfrac{100}{10} } \\\end{gathered}$

$\begin{gathered}\qquad \quad {:} \longrightarrow\sf \: \underline{ \boxed {\sf{mass = 10 \: kg }}} \\\end{gathered}$

➋ We know that:–

$\qquad \bull \bf \: { Potential \: energy=mass \times acceleration \times height}$

$\begin{gathered}\qquad \quad {:} \longrightarrow\sf \: {potential \: energy = 10 \times 10 \times 10 } \\\end{gathered}$

$\begin{gathered}\qquad \quad {:} \longrightarrow \underline{ \boxed{\sf \: {potential \: energy = 1000 \: J}}} \\\end{gathered}$

$\begin{gathered}\large \quad \therefore\sf \: { The \: correct \: option \: is \: \underline{\underline{1000 \: J}}} \\\end{gathered}$

$\large{\underline{\underline{\sf{ \maltese \: {Answer:-}}}}}$

• The potential energy is 1000 J.

Answer 2

Answer:

1000 J

Explanation:

Given:−

Weight = 100 N

Height = 10 m

\large{\underline{\underline{\sf{ \maltese \: {To \: find:-}}}}}✠Tofind:−

Potential energy = ?

\large{\underline{\underline{\sf{ \maltese \: {Solution:-}}}}}✠Solution:−

➊ We know that:–

\qquad \bull \bf \: {Weight =

We know that:–

\qquad \bull \bf \: { Potential \: energy=mass \times acceleration \times height}∙Potentialenergy=mass×acceleration×height

\begin{gathered} \qquad \quad {:} \longrightarrow\sf \: {potential \: energy = 10 \times 10 \times 10 } \\ \end{gathered}:⟶potentialenergy=10×10×10

\begin{gathered} \qquad \quad {:} \longrightarrow \underline{ \boxed{\sf \: {potential \: energy = 1000 \: J}}} \\ \end{gathered}:⟶potentialenergy=1000J

\begin{gathered} \large \quad \therefore\sf \: { the \: correct \: option \: is \: \underline{\underline{1000 \: J}}} \\ \end{gathered}∴thecorrectoptionis1000J

\large{\underline{\underline{\sf{ \maltese \: {Answer:-}}}}}✠Answer:−

The potential energy is 1000 J

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