A box of weight 200 N is kept on the floor. The area of contact is 4m^2. The pressure exerted by the box on the floor is -
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Answer:
0.01 m²
Explanation:
Given:
Weight of the box = 200 N (i.e, the force exerted by the box)
Pressure exerted by the box = 20,000 Pa
To find:
Contact Area of the box with the floor
Method to find:
Pressure = Force / Area
⇒ 20,000 = 200/Area
⇒ Area = 200/20,000
⇒ Area = 0.01 m²
Hence, the box is in contact with 0.01 m² of the floor.
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