Question

A box slides down an inclined plane with a uniform acceleration and attains a velocity of 27 m/s in 3 seconds from rest. Find the final velocity and distance moved in 6 seconds (initially at rest).

Answer 1

u=0 m/s

t=3sec

v=27m/s

then,

a=v-u/t

=27-0/3

=9m/s^2

And After 6 Sec:-

v=? and s=?

v=u+at

=0+9(6)

=56m/s

and

s=ut+1/2at^2

=0×6+1/2×9×(6)^2

=162m

where,

s=Distance

v=Final Velocity

#Hope This Answer Helps You..