. A boy 2m tall is standing at some distance from a 30m tall building. The angle of elevation from his eyes to the top of the building increases from 30 degree to 60 degree as he walks towards the building. Find the distance he walked? *
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Answer:
REF.Image
AB= 30-1.5=28.5 cm
In ΔABD:−tan30
∘
=
BD
AB
⇒BD=(28.5)
3
In ΔABC:−tan60
∘
=
BC
AB
⇒BC=
3
(28.5)
CD= BD-BC
=28.5(
3
−
3
1
)
=28.5(
3
2
)=32.91m
see the image
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