Question

. A boy 60 kg hops with a horizontal velocity of 5 ms-1 on a stationary skateboard.

The skateboard weighs 4 kg. Find out the velocity when the board starts rolling?

The condition given here is that any external unbalanced force is absent.​

Answer 1

Answer:

Let v be the velocity of the girl on the cart as the cart starts moving.

The total momenta of the girl and cart before the interaction = (50 x 5 m s-1) + (4 x 0 m s-1)

                                                                           = 250 kg m s-1

The total momenta after the interaction = (50 + 4) kg x v m s-1

                                                              = 54 v kg m s-1

According to the law of conservation of momentum,

Total momentum before the interaction = Total momentum after the interaction

→ 54 v = 250

→ 

PLZ MARK AS BRAINLIEST

Explanation:

Answer 2

Explanation:

thanks a lot for answering