A boy bursts a balloon. The other boy hears the sound after 6 s . If the speed of sound is 330 ms-1, find the distance between the two boys.
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ANSWER
Distance of person from nearer cliff, (d
1
)
=
2
v×t
⇒d
1
=
2
330×3
=495m
Distance of person from farther cliff, d
2
=
2
v×t
d
2
=
2
330×5
=825m
Total distance between two cliffs
=d
1
+d
2
=(495+825)
=1320m.
solution
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