Question

A boy can throw a ball to maximum height of 10 m, if projected vertically. the horizontal distance that the boy can throw the same ball with same speed if projected at angle 45° with horizontal will be

Answer 1

h=10
u^2/2g=10
u^2=200
u=10√2
Now
R=u^2sin2(theta)/g
R=200×sin90°/10
R=20