Question

a boy can throw a ball to maximum hieght of 10m ,if projected vertically. The horizontal distance that the boy can throw the same ball with same speed if projected at an angle 45° with horizontal will be?

Answer 1

90°= 10 m; 45° = 20 m

Answer 2

h is 10 m. so by. conservation of energy. kinetic energy at bottom is equal to potential energy at top. so. 0.5×m×v^2=. m×g×h. from here. v=10√2. and. formula for max range is. 2u^2sin^2 45/g. so. 2× 200/2×10. ie 20 m