Question

A boy can throw a stone up to a maximum height of 10m. The maximum horizontal distance that the boy can throw the same stone will be :

20m
20.2m
10m
10.2m

Answer 1

Given:-

☆Maximum height the boy can throw the stone=10m

To find:-

☆Maximum horizontal distance,that the boy can throw the same stone.

Solution:-

We know that:-

=>h max=u²/2g

=>u²=2gh

=>u²=2×10×10

=>u²=200 -----(1)

Now:-

=>R max=u²/g

=>200/10 (putting value of u² from eq.1)

=>20m

Thus,maximum horizontal distance that the boy can throw the stone is 20m.

Answer 2

Given :-

• A boy can throw a stone up to a maximum height of 10m.

To Find :-

• The maximum horizontal distance that the boy can throw the same stone.

Solution :-

As we know that,

$\sf h \: max = \frac{u^{2}}{2g}$

$\sf\implies u^{2} = 2gh$

$\sf\implies u^{2} = 2 \times 10 \times 10$

$\sf\implies u^{2} = 200 \: ---- \: (1)$

We need to find the maximum horizontal distance that the boy can throw the same stone :-

We know that,

$\sf R \: max = \frac{u^{2}}{g}$

Putting the value of u² we get,

$\sf\implies \frac{200}{10}$

$\sf\implies\boxed{\sf 20m}$

Thus, the maximum horizontal distance that the boy can throw the same stone is 20m.